If it's not what You are looking for type in the equation solver your own equation and let us solve it.
3x^2-4=143
We move all terms to the left:
3x^2-4-(143)=0
We add all the numbers together, and all the variables
3x^2-147=0
a = 3; b = 0; c = -147;
Δ = b2-4ac
Δ = 02-4·3·(-147)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*3}=\frac{-42}{6} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*3}=\frac{42}{6} =7 $
| 3(x+9)=2x-2 | | 1/4x+2=8x+9/8 | | 6x+7=13+7x-3x | | -14+38=-3(x+3) | | 254+82=k+78 | | 6(z+3)-3z=60 | | 3x-6=9+9x | | 0=4+n/5= | | -29=5w=6-12w | | 4.8+6.3=7x-2.7-6x | | 10y+-10y=0y | | 2x+(×+2)=5x-10 | | 1/4w+2=3/4 | | 5b+8+3b+4=40 | | 5b+8+3b+4=40-8 | | 10y+-10y=0 | | 5b+8+3b+4=40-4+4 | | -10x+1=-x+10 | | 5x+(-6x)=17 | | (7x-2)=(3x+5) | | 4z+5/4=7z-2/7 | | -4(5-2x)-10x=6 | | 2/3c-26/3=7 | | 8.1/x=5.9/2 | | 8+k=-17 | | C-(4/3)c=10 | | x²-2x+2=0 | | 79=8x+15 | | (2x+4)+(6x-2)=42 | | 7x-20=-1 | | 5/6w=21=-1/3(2w-9) | | 0.18(y-8)+0.08y=0.10y-1 |